C program to accept a matrix of order M x N and find the sum of each row and each column of a matrix
Tuesday, 1 May 2012
/* C program to accept a
matrix of order M x N and find the sum of each row and each column of a matrix
*/
#include <stdio.h>
void
main ()
{
static int m1[10][10];
int i,j,m,n,sum=0;
{
static int m1[10][10];
int i,j,m,n,sum=0;
printf
(“Enter the order of the matrix\n”);
scanf (“%d %d”, &m,&n);
printf (“Enter the co-efficient s of the matrix\n”);
scanf (“%d %d”, &m,&n);
printf (“Enter the co-efficient s of the matrix\n”);
for
(i=0;i<m;++i)
{
for (j=0;j<n;++j)
{
scanf (“%d”,&m1[i][j]);
}
}
for (i=0;i<m;++i)
{
for (j=0;j<n;++j)
{
sum = sum + m1[i][j] ;
}
printf (“Sum of the %d row is = %d\n”,i,sum);
sum = 0;
}
{
for (j=0;j<n;++j)
{
scanf (“%d”,&m1[i][j]);
}
}
for (i=0;i<m;++i)
{
for (j=0;j<n;++j)
{
sum = sum + m1[i][j] ;
}
printf (“Sum of the %d row is = %d\n”,i,sum);
sum = 0;
}
sum=0;
for
(j=0;j<n;++j)
{
for (i=0;i<m;++i)
{
sum = sum+m1[i][j];
}
printf (“Sum of the %d column is = %d\n”, j,sum);
sum = 0;
}
} /*End of main() */
/*—————————————————
Output
Enter the order of the matrix
3 3
Enter the co-efficient s of the matrix
1 2 3
4 5 6
7 8 9
Sum of the 0 row is = 6
Sum of the 1 row is = 15
Sum of the 2 row is = 24
Sum of the 0 column is = 12
Sum of the 1 column is = 15
Sum of the 2 column is = 18
{
for (i=0;i<m;++i)
{
sum = sum+m1[i][j];
}
printf (“Sum of the %d column is = %d\n”, j,sum);
sum = 0;
}
} /*End of main() */
/*—————————————————
Output
Enter the order of the matrix
3 3
Enter the co-efficient s of the matrix
1 2 3
4 5 6
7 8 9
Sum of the 0 row is = 6
Sum of the 1 row is = 15
Sum of the 2 row is = 24
Sum of the 0 column is = 12
Sum of the 1 column is = 15
Sum of the 2 column is = 18
—————————————————-*/
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